题解 | #蛇形矩阵#
蛇形矩阵
https://www.nowcoder.com/practice/649b210ef44446e3b1cd1be6fa4cab5e
#include <stdio.h> int main() { int n; scanf("%d", &n); if (n > 0 && n <= 100) { int num[n][n]; for (int i = 0; i < n; i++) { if ( i == 0 ) { for (int j = 0; j < n; j++) { num[i][j] = num[i][j-1] + j + 1; num[0][0] = 1; } } else { for (int j = 0; j < n - i; j++) { num[i][j] = num[i-1][j+1] - 1; } } } for (int i = 0; i<n; i++) { for (int j = 0; j < n - i; j++) { if (num[i][j] != 0) { printf("%d ", num[i][j]); } } printf("\n"); }} return 0; }