题解 | #公共子串计算#
公共子串计算
https://www.nowcoder.com/practice/98dc82c094e043ccb7e0570e5342dd1b
s1 = input().strip() s2 = input().strip() t1 = 0 re = 1 for i in range(len(s1)): while s1[i:i+re] in s2 and i+re <= len(s1): re+=1 print(re-1)
公共子串计算
https://www.nowcoder.com/practice/98dc82c094e043ccb7e0570e5342dd1b
s1 = input().strip() s2 = input().strip() t1 = 0 re = 1 for i in range(len(s1)): while s1[i:i+re] in s2 and i+re <= len(s1): re+=1 print(re-1)
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