题解 | #牛牛的短信#
牛牛的短信
https://www.nowcoder.com/practice/435c9e2bf4f84bee99b82ce84e95b0b7
#include <stdio.h> int main() { int num,words; float price=0.0; scanf("%d",&num); int i; for(i=1;i<=num;i++) { scanf("%d",&words); if(words>60) price+=0.2; else if(words<=60&&words>=0) price+=0.1; } printf("%.1f",price); return 0; }