题解 | #单链表的排序#
单链表的排序
https://www.nowcoder.com/practice/f23604257af94d939848729b1a5cda08
import java.util.*; /* * public class ListNode { * int val; * ListNode next = null; * public ListNode(int val) { * this.val = val; * } * } */ public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 the head node * @return ListNode类 */ public ListNode sortInList (ListNode head) { // write code here if(head == null || head.next == null){ return head; } ListNode vNode; ListNode result = new ListNode(-1); vNode = result; ArrayList<Integer> temp = new ArrayList<Integer>(); // temp.add(head.val); while( head != null){ temp.add(head.val); head = head.next; } Collections.sort(temp); System.out.println(temp); for(int i=0;i<temp.size();i++){ ListNode tempNode = new ListNode(temp.get(i)); vNode.next = tempNode; vNode = vNode.next; } return result.next; } }