题解 | #计算某字符出现次数#

#include <stdio.h>

int main() {
    int counter[26+10+1] = {0};
    char c;
    while ((c = getchar()) != '\n') {
        if (c >= 'a' && c <= 'z') { // 小写字母
            c = c-'a';
            counter[c]++;
        } else if (c >= 'A' && c <= 'Z') {
            c = c-'A';
            counter[c]++;
        } else if (c >= '0' && c <= '9') {
            c = c-'0'+26;
            counter[c]++;
        } else if (c == ' ') {
            counter[36]++;
        }
    }
    c = getchar();
    if (c >= 'a' && c <= 'z') { // 小写字母
            c = c-'a';
        } else if (c >= 'A' && c <= 'Z') {
            c = c-'A';
        } else if (c >= '0' && c <= '9') {
            c = c-'0'+26;
        } else if (c == ' ') {
            c = 36;
        }
    printf("%d\n", counter[c]);
    
    return 0;
}