题解 | #数值的整数次方#
数值的整数次方
https://www.nowcoder.com/practice/1a834e5e3e1a4b7ba251417554e07c00
class Solution {
public:
double Power(double base, int exponent) {
double res=1;
if(exponent==0) return 1;
//先取绝对值计算幂，再判断正负
for(int i=1; i<=abs(exponent); i++){
res=res*base;
}
if (exponent>0) return res;
else return 1/res;
}
};
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