题解 | #Day of Week#

#include <iostream>
using namespace std;

string list[12] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};
string list2[7] = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday" };
int list3[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

int month(string s) {
    for (int i = 0; i < 12; i++) {
        if (s == list[i])
            return i + 1;
    }
    return 0;
}

int main() {
    int a, b;
    string s;
    //1 October 2001 Monday
    while (cin >> a >> s >> b) { // 注意 while 处理多个 case
        int all = 0;
        for (int i = 2001; i < b; i++) {
            if ((i % 4 == 0 && i % 100 != 0) || i % 400 == 0) {
                all += 366;
            } else {
                all += 365;
            }
        }
        for (int i = 1; i < month(s); i++) {
            all += list3[i - 1];
            if (i == 2 && ((b % 4 == 0 && b % 100 != 0) || b % 400 == 0))
                all++;
        }
        all += a;
        cout << list2[all % 7] << endl;
    }
}
// 64 位输出请用 printf("%lld")