题解 | #跳台阶#
跳台阶
https://www.nowcoder.com/practice/8c82a5b80378478f9484d87d1c5f12a4
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
#
# @param number int整型
# @return int整型
#
class Solution:
def jumpFloor(self , number: int) -> int:
# write code here
if number == 1:
return 1
res = [1, 2]
while len(res) < number:
n1, n2 = res[-1], res[-2]
res.append(n1 + n2)
return res[-1]
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