题解 | HJ_23 #删除字符串中出现次数最少的字符#
删除字符串中出现次数最少的字符
https://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
import java.util.List; import java.util.ArrayList; import java.util.HashMap; import java.util.Map; import java.util.Scanner; // 注意类名必须为 Main, 不要有任何 package xxx 信息 public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); String input = in.nextLine(); Map<Character, Integer> countMap = new HashMap<>(); char[] chars = input.toCharArray(); for (char c : chars) { countMap.put(c, countMap.getOrDefault(c, 0) + 1); } //找到出现次数最少的的字符 int minCount = countMap.values().stream().sorted().findFirst().get(); List<Character> removeChars = new ArrayList(); countMap.entrySet().stream().forEach(entry -> { if (entry.getValue() == minCount) { removeChars.add(entry.getKey()); } }); // for (char c : chars) { if (!removeChars.contains(c)) { System.out.print(c); } } System.out.println(); } }