题解 | #进制转换#

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void (async function () {
    // Write your code here

    while ((line = await readline())) {
        
        let tokens = line.split("");
        const hTn = {
            A: 10,
            B: 11,
            C: 12,
            D: 13,
            E: 14,
            F: 15,
        };
        let ans = 0;
        const sLen = tokens.length;
        for (let i = 2; i < tokens.length; i++) {
            if (tokens[i] < 10) {
                ans = ans + tokens[i] * Math.pow(16, sLen - 1 - i);
            }else{
                ans = ans + hTn[tokens[i]] * Math.pow(16, sLen - 1 - i);
            }
        }
        console.log(ans)
    }
})();

粗暴简单

和手写一样

Math.pow(base, exponent): 求base 的exponent次幂