题解 | #计算某字符出现次数#

#include <iostream>
using namespace std;

int main() {
    string a, b;
    while (getline(cin, a) && cin >> b) { // 注意 while 处理多个 case
        int numb = b[0];
        if (numb >= 'a' && numb <= 'z')
        {
            numb -= 32;
        }
        int numa = 0;
        int num = 0;
        for (int i = 0; i < a.size(); ++i)
        {
            numa = a[i];
            if ((numa >='a') && (numa <= 'z'))
            {
                numa -= 32;
            }

            if (numa == numb)
            {
                num++;
            }
        }
        cout << num << endl;
    }
}
// 64 位输出请用 printf("%lld")