题解 | #牛客每个人最近的登录日期(四)#
牛客每个人最近的登录日期(四)
https://www.nowcoder.com/practice/e524dc7450234395aa21c75303a42b0a
SELECT DATE
,SUM(CASE WHEN DATE=first_login THEN 1
ELSE 0 END) AS NEW
FROM
(
SELECT *
,MIN(DATE) OVER(PARTITION BY user_id ORDER BY DATE) AS first_login
FROM login
) AS t1
GROUP BY DATE
