题解 | #删除字符串中出现次数最少的字符#

import sys

dic = {}
for line in sys.stdin:
    s = line.split()[0]
    for i in range(len(s)):
        if dic.get(s[i], 0) == 0:
            dic[s[i]] = 1
        else:
            dic[s[i]] += 1
    min = 100
    for v in dic.values():
        if v < min:
            min = v
    for key in dic:
        if dic[key] == min:
            temp = ""
            for item in s.split(key):
                temp += item
            s = temp
    print(s)