题解 | #牛牛的水杯#
牛牛的水杯
https://www.nowcoder.com/practice/c196c47c23394bf3bdd4f82a838df6bf
#include<stdio.h>
int main()
{
int h = 0, r = 0;
scanf("%d %d", &h, &r);
int v = 3.14 * h * r * r;
int n = 0;
n = 10000 / v;
if (10000 % v > 0)
n=n + 1;
printf("%1d", n);
return 0;
}
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