题解 | #KiKi和酸奶#
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h>
int main() {
int n = 0;
int h = 0;
int m = 0;
do {
scanf("%d %d %d",&n,&h,&m);
}while (m > n*h);
if(m%h == 0)
printf("%d",n-m/h);
else
printf("%d",n-m/h-1);
return 0;
}
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