题解 | #牛牛学数列#
牛牛学数列
https://www.nowcoder.com/practice/0b97367cd2184c12a0e02f7c223aee11
#include <stdio.h>
int main() {
int i = 0;
int j = 0;
int sum = 0;
scanf("%d", &i);
for (j = 1; j <= i; j++) {
if (j % 2 == 0) {
sum += -j;
} else {
sum += j;
}
}
printf("%d", sum);
return 0;
}
