题解 | #2的n次方计算#
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h>
int main() {
int i = 0;
scanf("%d",&i);
int c = 2<<(i-1);
printf("%d",c);
}
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h>
int main() {
int i = 0;
scanf("%d",&i);
int c = 2<<(i-1);
printf("%d",c);
}
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