题解 | #时间转换#

#include <stdio.h>

int main() {
   int a  = 0;
   scanf("%d",&a);
   int b = a%3600;
   int c = a/3600;
   int d = b%60;
   if(c!=0)
   {
    printf("%d ",c);
   }
   else {
    printf("%d ",0);
   }
   if(b!=0)
   {
    printf("%d ",b/60);
   }
   else {
    printf("%d ",0);
   }
   if(d!=0)
   {
    printf("%d ",d);
   }
   else {
    printf("%d ",0);
   
   }
   return 0;
}