题解 | #密码强度等级#

# range(x, y) includes x up to but not including y. 
# So range(5, 7) is 5, 6 but not 7.

# !"#$%&'()*+,-./:;<=>?@[\]^_`{|}~
# !"#$%&\'()*+,-./:;<=>?@[\\]^\_`{|}~
# '\_ needs to be escaped


def length(s):
    if len(s) <= 4:
        return 5
    elif len(s) in range(5, 8):
        return 10
    else:
        return 25


def alpha(s):
    has_upper = 0
    has_lower = 0
    for char in s:
        if char.isupper():
            has_upper = 10
        elif char.islower():
            has_lower = 10
    return has_upper + has_lower


def digit(s):
    s2 = 0
    c2 = 0
    for char in s:
        if char.isdigit():
            s2 = 10
            c2 += 1
            if c2 > 1:
                s2 = 20
                break
    return s2


def symbol(s):
    symbols = '!"#$%&\'()*+,-./:;<=>?@[\\]^\_`{|}~'
    s3 = 0
    c3 = 0
    for char in s:
        if char in symbols:
            s3 = 10
            c3 +=1
            if c3 > 1:
                s3 = 25
                break
    return s3


def bonus(s):
    s4 = 0
    if alpha(s) and digit(s):
        s4 = 2
        if symbol(s):
            s4 = 3
            if alpha(s) == 20:
                s4 = 5
    return s4


def level(s):
    if s in range(0, 24):
        print('VERY_WEAK')
    elif s in range(25, 50):
        print('WEAK')
    elif s in range(50, 60):
        print('AVERAGE')
    elif s in range(60, 70):
        print('STRONG')
    elif s in range(70, 80):
        print('VERY_STRONG')
    elif s in range(80, 90):
        print('SECURE')
    else:
        print('VERY_SECURE')


pw = input()
score = length(pw) + alpha(pw) + digit(pw) + symbol(pw) + bonus(pw)
level(score)

# print(str(score), str(length(pw)), str(alpha(pw)), str(digit(pw)), str(symbol(pw)), str(bonus(pw)))

• 符号判断遇到了些阻碍，Claude用的是string.punctuation
• 创建一个字符串列表后还需要用\来Escape可能冲突的符号
• 对range()的边界条件不熟悉，它是不包括上边界的