题解 | #求最大连续bit数#

n = int(input())
count = 0
max_count = 0

while n > 0:
    bit = n & 1
    if bit == 1:
        count += 1
        max_count = max(max_count, count)
    else:
        count = 0
    n >>= 1

print(max_count)

用&将二进制n的最小位与1做与运算，记录连续1的个数，并输出最多个数

位右移n，直至为n=0跳出循环