题解 | #牛牛的digit#
牛牛的digit
https://www.nowcoder.com/practice/21b49f1f495f4280b8a96c415deaa3c4
#include <stdio.h>
int main() {
int x, i, sum = 0, t = 1;
scanf("%d %d", &x, &i);
while (i-- > 0) {
sum += (x % 10) * t;
t *= 10;
x /= 10;
}
printf("%d", sum);
return 0;
}
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