题解 | #输出单向链表中倒数第k个结点#

import sys
class ListNode:
    def __init__(self,Key):
        self.Key = Key
        self.next=None
class ListLink:
    def __init__(self):
        self.rear = None
    
    def add(self,Key):
        t = ListNode(Key)
        t.next = self.rear
        self.rear = t
while True:
    try:
        a = int(input())
        b = input().split()
        c = int(input())
        y = ListLink()
        for i in range(len(b)):
            y.add(b[i])
        d = y.rear
        if c == 1:
            print(d.Key)
        else:
            for i in range(c-1):
                d = d.next
            print(d.Key)
        if c == 0:
            print(0)       
    except:
        break