题解 | #有序序列合并#
有序序列合并
https://www.nowcoder.com/practice/a9e943b0dab142759807d0cfb6863897
#include <stdio.h>
int main()
{
int n = 0;
int m = 0;
scanf("%d %d", &n, &m);//第二行n个整数 第三行m个整数
int arr1[1000] = { 0 };//初始化数组
int arr2[1000] = { 0 };
int i = 0;
int j = 0;
for ( i = 0; i < n; i++)
{
scanf("%d", &arr1[i]);
}
for ( j = 0; j < m; j++)
{
scanf("%d", &arr2[j]);
}
i = 0;
j = 0;
while (i < n && j < m)
{
if (arr1[i] < arr2[j])
{
printf("%d ", arr1[i]);
i++;
}
else
{
printf("%d ", arr2[j]);
j++;
}
}
if (i == n && j < m)
for (; j < m; j++)
printf("%d ", arr2[j]);
else
for (; i < n; i++)
printf("%d ", arr1[i]);
return 0;
}