题解 | #字符串加密#
字符串加密
https://www.nowcoder.com/practice/e4af1fe682b54459b2a211df91a91cf3
k = list(input())
s = input()
lst = []
small = [chr(i) for i in range(ord('a'), ord('z') + 1)]
for i in k + small:
if i not in lst:
lst.append(i)
res = ''
for i in s:
ind = small.index(i)
res += lst[ind]
print(res)
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