题解 | #最长公共前缀#

    def longestCommonPrefix(self , strs: List[str]) -> str:
        # write code here
        count = len(strs)
        if count==0:
            return ""
        else:
            for i in range(len(strs[0])):
                temp = strs[0][i]
                for j in range(1,count):
                # len(strs[j])==i 退出
                # 确定此时strs[j][i]是存在的
                    if len(strs[j])==i or strs[j][i]!=temp:
                        return strs[0][0:i]
        return strs[0]