题解 | #统计成绩#

#include <stdio.h>

int main() {
    int n = 0;

    float arr[100] = {0};
    float max = 0;
    float min = 100;
    float ave = 0;
    scanf("%d", &n);
    for (int i = 0; i < n; i++) {
        scanf("%f", &arr[i]);
        if (arr[i] > max) {
            max = arr[i];
        }
        if (arr[i] < min) {
            min = arr[i];
        }
        ave += arr[i];
    }
    printf("%.2f %.2f %.2f\n", max, min, ave / n);
    return 0;
}