题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
list=[[1,2,3],[4,5,6],[7,8,9]]
n=int(input())
if n in range(1,10):
for i in range(0,len(list)):
for m in range(0,len(list[i])):
list[i][m]=n*list[i][m]
print(list)
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