题解 | #验证IP地址#

import re
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 验证IP地址
# @param IP string字符串 一个IP地址字符串
# @return string字符串
#
class Solution:
    def solve(self , IP: str) -> str:
        # write code here
        arr = IP.split('.')
        if len(arr) == 4:
            flag = True
            for clo in arr:
                if clo.startswith('0'):
                    flag = False
                    break
                else:
                    my_re = re.compile(r'[A-Za-z]', re.S)
                    res = re.findall(my_re, clo)
                    if len(res):
                        flag = False
                        break
                    else:
                        if int(clo) > 0 and int(clo) <= 255:
                            continue
                        else:
                            flag = False
                            break
            if flag:
                return "IPv4"
            else:
                return "Neither"
        else:
           arr = IP.split(':')
           if len(arr) == 8:
                flag = True
                for clo in arr:
                    if clo == '':
                        flag = False
                        break
                    else:
                        my_re = re.compile(r'[G-Zg-z]', re.S)
                        res = re.findall(my_re, clo)
                        if len(res):
                            flag = False
                            break
                        else:
                            if len(clo) > 4:
                                flag = False
                                break
                            else:
                                if int(clo,16) >= 0 and int(clo,16) <= 65535:
                                    continue
                                else:
                                    flag = False
                                    break  
                if flag:
                    return "IPv6"
                else:
                    return "Neither"
           else:
                return "Neither"