题解 | #数字颠倒#
数字颠倒
https://www.nowcoder.com/practice/ae809795fca34687a48b172186e3dafe
#include <iostream>
using namespace std;
int main() {
int a;
cin >> a;
string res;
if(a == 0){
cout << "0" << endl;
}
while(a > 0){
int b = a %10;
a = a/10;
res += ('0'+b);
}
cout << res << endl;
return 0;
}
// 64 位输出请用 printf("%lld")
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