题解 | #求两个数的差值#

`timescale 1ns/1ns
module data_minus(
	input clk,
	input rst_n,
	input [7:0]a,
	input [7:0]b,

	output  reg [8:0]c
);


always@(posedge clk or negedge rst_n)
  if(!rst_n)
    c <= 0;
  else if(a > b)
     c <= a - b;
  else
     c <= b - a;  

endmodule