题解 | #手套#
手套
https://www.nowcoder.com/practice/365d5722fff640a0b6684391153e58d8
#include <climits>
#include <random>
class Gloves {
public:
int findMinimum(int n, vector<int> left, vector<int> right) {
// write code here
int left_sum = 0, left_min = INT_MAX;
int right_sum = 0, right_min = INT_MAX;
int sum = 0;
//遍历每一种颜色的左右手套序列
for (int i = 0; i < n; i++) {
//对于有0存在的颜色手套,累加
if (left[i]*right[i] == 0)
sum += left[i] + right[i];
//对于左右手都有的颜色手套,执行累加-最小值+1
//找到最小值和总数
else {
left_sum += left[i];
right_sum += right[i];
left_min = min(left_min, left[i]);
right_min = min(right_min, right[i]);
}
}
//结果为有左右都有数量的手套序列的结果+有0存在的手套数+最后再加一肯定就能保证了
return sum + min(left_sum - left_min + 1, right_sum - right_min + 1) + 1;
}
};

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