题解 | #删除字符串中出现次数最少的字符#
删除字符串中出现次数最少的字符
https://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
import java.util.*; import java.util.stream.Collectors; // 注意类名必须为 Main, 不要有任何 package xxx 信息 public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); // 注意 hasNext 和 hasNextLine 的区别 while (in.hasNextLine()) { // 注意 while 处理多个 case System.out.println(deleteFewestChar(in.nextLine())); } } /** * HJ23 删除字符串中出现次数最少的字符 */ private static String deleteFewestChar(String str) { Map<Character, Integer> charMap = new HashMap<>(26); char[] arr = str.toCharArray(); for (char c : arr) { charMap.compute(c, (k, v) -> v == null ? 1 : v + 1); } int min = Collections.min(charMap.values()); String ss = charMap.entrySet().stream(). filter(entry -> entry.getValue() == min).map(Map.Entry::getKey).map(String::valueOf).collect(Collectors.joining()); return str.replaceAll("[" + ss + "]",""); } }