题解 | #KiKi和酸奶#
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include<stdio.h>
int main()
{
unsigned int n,h,m;//保证输入不为负数
if(m<=n*h)//限制条件
{
scanf("%u %u %u",&n,&h,&m);
int y=n-(m/h);//剩余酸奶盒数
if(m%h!=0)
{
y=y-1;
}
printf("%u",y);
}
return 0;
}
