题解 | #输出单向链表中倒数第k个结点#

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void (async function () {
    // Write your code here
    let arrinput = [];
    while ((line = await readline())) {
        arrinput.push(line);
    }
    const len=arrinput.length;
    for (i = 0; i < len; i += 3) {
        let arr = [];
        arr.push(arrinput.shift());
        arr.push(arrinput.shift());
        arr.push(arrinput.shift());
        let arrL = arr[1].split(" ");
        let k = arr[2];
        console.log(arrL[arrL.length - k]);
    }
})();