题解 | #牛群的合并#
牛群的合并
https://www.nowcoder.com/practice/d0cb24e1494e4f45a4b7d1a17db0daef?tpId=354&tqId=10594763&ru=/exam/oj/ta&qru=/ta/interview-202-top/question-ranking&sourceUrl=%2Fexam%2Foj%2Fta%3FtpId%3D354
知识点:小顶堆
解题思路:用小顶推存储节点,由于小顶堆的特性,Pop出的就是最小的,将其加入结果res,同时判断其Next是否为空,不为空则放入小顶堆。一直重复上序步骤,知道小顶堆为空
package main
import "container/heap"
import . "nc_tools"
/*
* type ListNode struct{
* Val int
* Next *ListNode
* }
*/
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param lists ListNode类一维数组
* @return ListNode类
*/
type SmallHeap []*ListNode
func (h SmallHeap) Less(i, j int) bool { return h[i].Val < h[j].Val }
func (h SmallHeap) Swap(i, j int) { h[i], h[j] = h[j], h[i] }
func (h SmallHeap) Len() int { return len(h) }
func (h *SmallHeap) Push(x interface{}) { *h = append(*h, x.(*ListNode)) }
func (h *SmallHeap) Pop() interface{} {
n := len(*h)
ans := (*h)[n-1]
*h = (*h)[:n-1]
return ans
}
func mergeKLists(lists []*ListNode) *ListNode {
// write code here
h := SmallHeap{}
heap.Init(&h)
for _, list := range lists {
if list != nil {
heap.Push(&h, list)
}
}
res := &ListNode{}
cur := res
for len(h) > 0 {
min := heap.Pop(&h).(*ListNode)
cur.Next = min
cur = cur.Next
if min.Next != nil {
heap.Push(&h, min.Next)
}
}
return res.Next
}
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