题解 | #二进制中1的个数#
二进制中1的个数
https://www.nowcoder.com/practice/8ee967e43c2c4ec193b040ea7fbb10b8
class Solution {
public:
int NumberOf1(int n) {
int count_ = 0;
while (n) {
count_++;
n = n & (n - 1);
}
return count_;
}
};
