题解 | #删除链表的节点#
删除链表的节点
https://www.nowcoder.com/practice/f9f78ca89ad643c99701a7142bd59f5d
package main /* * type ListNode struct{ * Val int * Next *ListNode * } */ /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 * @param val int整型 * @return ListNode类 */ func deleteNode( head *ListNode , val int ) *ListNode { // write code here // 使用哑节点统一节点的处理 dummy := &ListNode{Next: head} pre := dummy for head != nil { if head.Val == val { pre.Next = head.Next head = head.Next continue } pre = head head = head.Next } return dummy.Next }