题解 | #获取每个部门中当前员工薪水最高的相关信息#

select c.dept_no as dept_no,c.emp_no as emp_no,c.salary as maxSalary
from(select a.dept_no,a.emp_no,b.salary,dense_rank() over(partition by dept_no order by salary desc) as rank_id
from (dept_emp a)
inner join salaries b
on a.emp_no = b.emp_no) AS c
where c.rank_id = 1