题解 | #牛牛的短信#
牛牛的短信
https://www.nowcoder.com/practice/435c9e2bf4f84bee99b82ce84e95b0b7
#include <stdio.h>
int main() {
int n;
scanf("%d",&n);
float menoy=0;
float sum=0;
int number;
while(scanf("%d",&number)!=EOF){
if(number>60){
menoy=0.2;
}else {
menoy=0.1;
}
sum+=menoy;
}
printf("%f\n",sum);
return 0;
}
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