题解 | #字符串排序#

while True:
    try:
        n = int(input())
        sortDict = {}
        for i in range(n):
            strvalue = input()
            keyvalue = strvalue[0]
            if keyvalue in sortDict:
                sortDict[keyvalue].append(strvalue)
            else:
                sortDict[keyvalue] = []
                sortDict[keyvalue].append(strvalue)

        for i in range(len(sortDict)):
            minKey = min(sortDict.keys())
            minValue = sortDict.pop(minKey)
            # 对列表的值进行排序
            minValue.sort()
            print('\n'.join(minValue))
    except:
        break