题解 | #牛客的课程订单分析(七)#

select 
     distinct ifnull(c.name,'GroupBuy') as source
    ,a.cnt as cnt
from 
(
select 
    user_id
    ,client_id
    ,count(user_id)over(partition by client_id) cnt 
    ,count(user_id)over(partition by user_id) r
from 
    order_info
where datediff(date,'2025-10-15')>0
and status='completed' 
and product_name in ('C++','Java','Python') 
) a 
left join 
    client c 
on 
    a.client_id=c.id 
where 
    a.r>=2 
order by 
    source