题解 | #旋转数组的最小数字#
旋转数组的最小数字
https://www.nowcoder.com/practice/9f3231a991af4f55b95579b44b7a01ba
class Solution {
public:
int minNumberInRotateArray(vector<int> rotateArray) {
if(rotateArray.size()==0){
return 0;
}
int i=0,j=rotateArray.size()-1;
//循环
while(i<j){
int mid=i+((j-i)>>1);
if(rotateArray[mid]<rotateArray[j]){
j=mid;
}else if(rotateArray[mid]>rotateArray[j]){
i=mid+1;
}else{
j-=1;
}
}
return rotateArray[i];
}
};

