题解 | #删除链表的节点#

/**
 * struct ListNode {
 *	int val;
 *	struct ListNode *next;
 * };
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 
 * @param head ListNode类 
 * @param val int整型 
 * @return ListNode类
 */
struct ListNode* deleteNode(struct ListNode* head, int val ) {
    struct ListNode* cur = head;
    struct ListNode* prev = NULL;
    while(cur&&cur->val!=val)
    {
         if(cur->val==val)
         break;
         prev = cur;
         cur = cur->next;
    }
    if(cur==NULL)
    {
        return head;
    }
    if(prev==NULL)
    {
        head = cur->next;
    }
    else{
        prev->next = cur->next;
    }
    free(cur);
    return head;
   
}