题解 | #矩阵转置#

注意转置的时候，只对上三角或者下三角操作即可，如果对全部矩阵每一个元素都换一次，则操作回原矩阵，输出就会没区别

#include <iostream>
using namespace std;

#define N 100
int main(){
	int n;
	while (cin >>n && n != 0){
		int a[N][N];
		int i,j;
	  //输入
		for (i = 0; i < n;i++){
			for (j = 0; j < n; j++){
				cin >>a[i][j];
			}
		}
		//转置
		for (i = 0; i < n;i++){
			for (j = i; j < n; j++){
				int temp = a[i][j];
				a[i][j] = a[j][i];
				a[j][i] = temp;
			}
		}

		//输出
		for (i = 0; i < n;i++){
			for (j = 0; j < n; j++){
				cout <<a[i][j]<<" ";
			}
			cout <<endl;
		}
	}
}