题解 | #日期累加#

#include<cstdio>
int main(){
    int m;//样例个数
    int m_day[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
    scanf("%d",&m);
    for(int index=0;index<m;++index){
        int year,month,day;
        int date_accumulate;//累加日期
        scanf("%d%d%d%d",&year,&month,&day,&date_accumulate);
        for(int i=0;i<date_accumulate;++i){
            if(year%400==0 || year %100!=0 && year%4==0){
                m_day[2]=29;
            }else{
                m_day[2]=28;
            }
            ++day;
            if(day>m_day[month]){
                day=1;
                ++month;
                if(month>12){
                    month=1;
                    ++year;
                }
            }
        }
        printf("%4d-%02d-%02d\n",year,month,day);
    }
}