题解 | #计算日期到天数转换#
计算日期到天数转换
https://www.nowcoder.com/practice/769d45d455fe40b385ba32f97e7bcded
#include <stdio.h>
int main()
{
int year=0;
int month=0;
int day=0;
scanf("%d %d %d",&year,&month,&day);
int months[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 };
if((year%4==0&&year%100!=0)||(year%400==0))
{
months[1]=29;
}
int i=0;
int days=0;
for(i=0;i<month-1;i++)
{
days+=months[i];
}
printf("%d\n",days+day);
return 0;
}
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ps资格证书多了一行，最好精简成一面，hr看不了那么多字