题解 | #博客地址修复#
博客地址修复
https://www.nowcoder.com/practice/65e0929cba9a42ed8c119c532fbf40f0
写复杂了。。。。嗯。。。。
select device_id,( case when substr(d.a, 7, 1) = '/' then trim(d.a) when substr(d.a, 7, 1) <> '/' then trim(replace(d.a, 'http:/', 'http://')) end ) blog_url from( select device_id,trim(blog_url) a from user_submit ) d