题解 | #在二叉树中找到两个节点的最近公共祖先#
在二叉树中找到两个节点的最近公共祖先
https://www.nowcoder.com/practice/e0cc33a83afe4530bcec46eba3325116
递归写法,非递归写法太麻烦,索性写了
import java.util.*; /* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * } */ public class Solution { /** * * @param root TreeNode类 * @param o1 int整型 * @param o2 int整型 * @return int整型 */ public int lowestCommonAncestor (TreeNode root, int o1, int o2) { // write code here if (root == null) return -1; if (root.val == o1 || root.val == o2) return root.val; int left = lowestCommonAncestor(root.left, o1, o2); int right = lowestCommonAncestor(root.right, o1, o2); if (left != -1 && right != -1) return root.val; if (left != -1 && right == -1) return left; if (left == -1 && right != -1) return right; return -1; } }