题解 | #链表中倒数最后k个结点#
链表中倒数最后k个结点
https://www.nowcoder.com/practice/886370fe658f41b498d40fb34ae76ff9
快慢指针，快的先走K步（慢的停K步），让K递减，以K<=0为判断是快慢走还是只有快走。最后，快的到尾部None，慢的就到了倒数第K步。
class Solution: def FindKthToTail(self, pHead: ListNode, k: int) -> ListNode: a, b = pHead, pHead while a: if k <= 0: b = b.next a = a.next k = k - 1 return b if k <= 0 else None
