题解 | #根据状态转移图实现时序电路#
根据状态转移图实现时序电路
https://www.nowcoder.com/practice/e405fe8975e844c3ab843d72f168f9f4
`timescale 1ns/1ns
module seq_circuit(
input C ,
input clk ,
input rst_n,
output wire Y
);
parameter STATE0=2'b00;
parameter STATE1=2'b01;
parameter STATE2=2'b10;
parameter STATE3=2'b11;
reg[1:0] state,next_state;
always@(*)
case(state)
STATE0:next_state=C?STATE1:STATE0;
STATE1:next_state=C?STATE1:STATE3;
STATE2:next_state=C?STATE2:STATE0;
STATE3:next_state=C?STATE2:STATE3;
default:next_state=STATE0;
endcase
always@(posedge clk or negedge rst_n)
if(~rst_n)
state<=STATE0;
else
state<=next_state;
assign Y=((state==STATE2)&(C==1))|(state==STATE3);
endmodule
module seq_circuit(
input C ,
input clk ,
input rst_n,
output wire Y
);
parameter STATE0=2'b00;
parameter STATE1=2'b01;
parameter STATE2=2'b10;
parameter STATE3=2'b11;
reg[1:0] state,next_state;
always@(*)
case(state)
STATE0:next_state=C?STATE1:STATE0;
STATE1:next_state=C?STATE1:STATE3;
STATE2:next_state=C?STATE2:STATE0;
STATE3:next_state=C?STATE2:STATE3;
default:next_state=STATE0;
endcase
always@(posedge clk or negedge rst_n)
if(~rst_n)
state<=STATE0;
else
state<=next_state;
assign Y=((state==STATE2)&(C==1))|(state==STATE3);
endmodule